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Finding more minimum and maximum values in quadratic expressions part five



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  • 分级:普通级(General) - 全年龄皆可观看
  • 发布时间:2021-12-01 10:19

Finding more minimum and maximum values in quadratic expressions part five



Complete the square in (6x² - 13x + 6) and find its minimum value and the x-value where the minimum value occurs.

6x² - 13x + 6 = {(12x - 13)² - 25} / 24

6x² - 13x + 6 >= -25 / 24

{(12x - 13)² - 25} / 24 >= -25 / 24

minimum value = -25 / 24

(12x - 13)² = 0

x = 13 / 12

 

Complete the square in (10x² - 29x + 10) and find its minimum value and the x-value where the minimum value occurs.

10x² - 29x + 10 = {(20x - 29)² - 441} / 40

10x² - 29x + 10 >= -441 / 40

{(20x - 29)² - 441} / 40 >= -441 / 40

minimum value = -441 / 40

(20x - 29)² = 0

x = 29 / 20

 

Complete the square in (15x² - 34x + 15) and find its minimum value and the x-value where the minimum value occurs.

15x² - 34x + 15 = {(15x - 17)² - 64} / 15

15x² - 34x + 15 >= -64 / 15

{(15x - 17)² - 64} / 15 >= -64 / 15

minimum value = -64 / 15

(15x - 17)² = 0

x = 17 / 15


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0 只兽收藏了此作品
  • 浏览量:488
  • 分级:普通级(General) - 全年龄皆可观看
  • 发布时间:2021-12-01 10:19