Show that 4x² - 20x + 25 = 0 has only one solution.
First method
4x² - 20x + 25 = 0
(2x - 5)² = 0
x = 5 / 2
Second method
4x² - 20x + 25 = 0
a = 4, b = -20 and c = 25
b² = 400
4ac = 400
b² = 4ac
-b / (2a) = 5 / 2
Show that 4x² - 20x + 25 = 0 has only one solution.
First method
4x² - 20x + 25 = 0
(2x - 5)² = 0
x = 5 / 2
Second method
4x² - 20x + 25 = 0
a = 4, b = -20 and c = 25
b² = 400
4ac = 400
b² = 4ac
-b / (2a) = 5 / 2
