Show that 25x² - 20x + 4 = 0 has only one solution.
First method
25x² - 20x + 4 = 0
(5x - 2)² = 0
x = 2 / 5
Second method
25x² - 20x + 4 = 0
a = 25, b = -20 and c = 4
b² = 400
4ac = 400
b² = 4ac
-b / (2a) = 2 / 5
Show that 25x² - 20x + 4 = 0 has only one solution.
First method
25x² - 20x + 4 = 0
(5x - 2)² = 0
x = 2 / 5
Second method
25x² - 20x + 4 = 0
a = 25, b = -20 and c = 4
b² = 400
4ac = 400
b² = 4ac
-b / (2a) = 2 / 5
