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Finding more minimum and maximum values in quadratic expressions part one



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  • 分級:普通級(General) - 全年齡皆可觀看
  • 發佈時間:2021-12-01 09:57

Finding more minimum and maximum values in quadratic expressions part one



Complete the square in (4x² - 16x + 15) and find its minimum value and the x-value where the minimum value occurs.

4x² - 16x + 15 = (2x - 4)² - 1

4x² - 16x + 15 >= -1

(2x - 4)² - 1 >= -1

minimum value = -1

(2x - 4)² = 0

x = 2

 

Complete the square in (6x² - 19x + 15) and find its minimum value and the x-value where the minimum value occurs.

6x² - 19x + 15 = {(12x - 19)² - 1} / 24

6x² - 19x + 15 >= -1 / 24

{(12x - 19)² - 1} / 24 >= -1 / 24

minimum value = -1 / 24

(12x - 19)² = 0

x = 19 / 12

 

Complete the square in (6x² - 25x + 25) and find its minimum value and the x-value where the minimum value occurs.

6x² - 25x + 25 = {(12x - 25)² - 25} / 24

6x² - 25x + 25 >= -25 / 24

{(12x - 25)² - 25} / 24 >= -25 / 24

minimum value = -25 / 24

(12x - 25)² = 0

x = 25 / 12


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0 只獸收藏了此作品
  • 瀏覽量:362
  • 分級:普通級(General) - 全年齡皆可觀看
  • 發佈時間:2021-12-01 09:57